Stanley A Meyer
Understanding the VIC
Yes this is Priceless Rare Data of Stanley A Meyer and Knowledge suggest you back up all of it immediately and share it to others.
The time has come to tell my story how Stan Meyers Fuel Cell Works. October the 23th 2016
First! This Builder wanted to have a disclaimer statement. I he and others will not be responsible for anyone that uses this information in this thread to create any type of voltage and current either high or low of either of the two.
You take full responsibility of your own actions and the use of any information that is discussed in this thread. "High Voltage and Current can KILL You" This thread, and the post in this thread made by me or others, is for information use only.
Second! It is assumed that anyone that uses this information has at least the basic knowledge of electronics, formulas and equations. Therefor I will not be held responsible for anyone that uses this information, and can not get a Fuel Cell to work
Several years back a builder made the discovery how Stan was able to produce gas on demand for the second time. Like everyone else I keep throwing voltage to the water hoping to see it just fall apart into Hydrogen and Oxygen with no luck at all.
Like everyone else, with very little production of the two gases. (Due to Amp Leakage)
The Event Horizon
He came across a drawing in Stan's Tech Brief that clearly shows their is amp leakage in the cell.
(Which I will Post below)
Like everyone else, I thought the resonant reaction Stan talked about, was on the water itself.
When in fact the resonate action will only take place when the water is removed from within the cells.
Then an only then will the two choke coils come together and interact with one another.
As long as there is water between the cells, the two choke coils will not interact with each other which will stop any resonance to occur between the two due to the dead short. (Water),
( spark gap with no spark but plasma) like a spark gap the plasm gap has all the frequencies in it . )
Stan states, that you must overcome the dead short condition before resonance will occur
and allow the voltage to take over and do the work.
This is were everyone including me took this statement way out of context.
It dose not mean applying a high voltage to the water and it will just go away.
It means removing the water within the cells, which is a dead short condition in order to over come it.
aka Negative water radicals
So the question is how do we remove the dead short condition so the coils can interact with one another?
The answer is Amp leakage within the cell.
So how do we create this Amp leakage in the cell?
The answer is with the L1 Choke Inductive Reactance and the Cell Capacitance Reactance.
When you design the choke and the cell it has to meet certain criteria.
When you subtract the two from one another you don't want the math to come out to zero.
What you want is a ohm value left over.
That ohm value is what is going to cause the Amp leakage within the cell.
This is where you get into voltage leading the current or voltage lagging the current, depending on if the net value of ohms is capacitive or inductive. Electron EEC Extration
So in other words as the voltage increases so does the amp leakage.
At a certain point of increased voltage the water will be remove from the cell and will be replace with gas.
it does not mean dry it means the cas polarities make a nano bubles chain casuing a change
with majority of charges present between the tubes. like snoke flakes forming but linked togther,
This is where the resonate reaction will occur between the two chokes and the voltage will take off to infinity and the amps will drop to nearly nothing. (Voltage taking over and doing the work). Since all coils are adding one another.
In the drawing
I have colored it showing the water in blue and gas in yellow.
As you can see there is amp leakage that causes the water to be removed and replaced with gas or gasses.
Once this is achieved and only when this is achieve is when you will see a resonate condition take place to make Stan Meyers Water Fuel Gas on Demand. THE SATURATION POINT
As you can see we don't want resonance to occur until the water is removed.
In fact we are using the water itself to prevent it from occuring until the water is removed at the same time as the maximun applied voltage is reached.
It is also noted water should be cold and lid on to keep pressure in cell.
What happens in relationship to L2 before the Water being "removed"?
The resistance in the coil of wire on the L2 choke is used as to restrict amps as well.
It will not become part of aiding the voltage until resonance occurs.
Only when the water is removed will the two choke interact with one another.
As Stan states the water is part of the circuit, but once the water is removed you are left with the resistance of the wire used in the coils.
The water itself
and the amount of amp leakage gives you control to reach maxumim voltage
before resonance occurs.
So, the coil behaves only resistive at this time? Or reactive to?
The L1 coke is inductive and the l2 is resistive until the water is removed then it becomes inductive and aids to the voltage when resonace occurs..
People talks about frequency doubling the wrong way. Frequency doubling will not and does not occur until the water is removed and resonance takes place.
Also step charging is taking out of context also. Step charging only occurs as the water is being removed. Once the water is removed and resonance takes place you want see step charging anymore. It's not something you will see that still stay's on your scope. All you will see on the scope is the two chokes interacting with one another and their resonate reaction with one another once resonance is achieved. You have to start the process over again in order to see step charging take place again, or lower and raise the voltage.
So we are still after resonance, but only when the cell is empty of water. In this condition, if things are tuned properly, we should be able to waive a fluorescent bulb near the cell and see the glow from the high voltage.
I would call that basically
to ensure the VIC is actually working as it should.
One might want to connect a high voltage oscilloscope probe and verify, but really all that is needed is something to indicate there is a couple thousand volts per water cap (individual cell).
that you just went into is intentionally creating amp leakage, otherwise known as brute force electrolysis. We need this to electrically separate the plates--make them a true capacitor by removing the dead short.
This is where all the bunk about coating the plates goes out the window. The raw stainless is fine once we have gas between them and not all water.
And once we have gas, the voltage in there will prevent water from returning. The voltage will jump and stay that way under the resonant conditions.
So here's my question about step two: Is the amp leakage needed in proportion to the cell and/or plates? Meaning, if the plates are large, more amp leakage is needed to create sufficient gas where the voltage can begin to rise.
But... There is a limit, if we attempt to draw too many amps from those small gauge wires, it's game over. So the VIC dictates the dimensions of the cell.
It would also seem the cell could be too small allowing the voltage in the VIC to climb too high, also another disaster when the wires begin to arc over.
So if you would Ronnie, can you confirm to us that there needs to be a pretty decent match between the cell and the VIC--get outside the boundaries and the VIC smokes.
Or... Is the voltage produced by the VIC limited to the Q-factor of the resonant components--coils and water cap?
Let me try and answer one question at a time.
Amp leakage needed is not due to surface area or the length of cells, It is due to the gap of the cell and the amount of water that needs to be removed and the voltage your are trying to achieve.
You want the water to be removed at the same rate as voltage applied. in other words you don't want the water removed at 6 volts and resonance to occur when your wanting to apply 12 volt to the primary.
The more high voltage you can apply to the gas the more excited it will be and will become a more powerful gas.It is something you have to control with math when designing the vic and cell.
The smaller the water gap, therefore it takes less amp leakage due to less water to be removed. As you see this in the water injector.
You are exactly right Matt, you can not draw more current than the wire you use will allow. This is where everyone needs to be careful, once resonance occurs the voltage will climb towards infinity even with the smallest amount of current in the secondary side,
if knocked out of tune it will make toast out of your VIC in an instant. Unlike those, that allows people to set and turn knobs, You cannot allow anyone to tune anything once resonance is achieved.
And to answer your question about match between the Vic and Cell, yes it has to be a matched by design, you want all cells to have close to a perfect match as you can get. That way you have the same voltage across each cell, which will require the same Amp leakage to remove the water at the same time.
You want the resonance to occur at the same time in each cell.
People have made the statement many times,
There is no way Stan could be producing enough gas to run an engine.
The Fact is Stan doesn't have to produce a lot of gas to run a ca